log(x^2)+1=log(3x+1)

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Solution for log(x^2)+1=log(3x+1) equation:


Simplifying
log(x2) + 1 = log(3x + 1)

Multiply glo * x2
glox2 + 1 = log(3x + 1)

Reorder the terms:
1 + glox2 = log(3x + 1)

Reorder the terms:
1 + glox2 = glo(1 + 3x)
1 + glox2 = (1 * glo + 3x * glo)
1 + glox2 = (1glo + 3glox)

Solving
1 + glox2 = 1glo + 3glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1glo' to each side of the equation.
1 + -1glo + glox2 = 1glo + -1glo + 3glox

Combine like terms: 1glo + -1glo = 0
1 + -1glo + glox2 = 0 + 3glox
1 + -1glo + glox2 = 3glox

Add '-3glox' to each side of the equation.
1 + -1glo + -3glox + glox2 = 3glox + -3glox

Combine like terms: 3glox + -3glox = 0
1 + -1glo + -3glox + glox2 = 0

Add '-1' to each side of the equation.
1 + -1glo + -3glox + -1 + glox2 = 0 + -1

Reorder the terms:
1 + -1 + -1glo + -3glox + glox2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1glo + -3glox + glox2 = 0 + -1
-1glo + -3glox + glox2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1glo + -3glox + glox2 = -1

Reorder the terms:
1 + -1glo + -3glox + glox2 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -1glo + -3glox + glox2 = 0

The solution to this equation could not be determined.

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